(8x^-4y^2/-2x^2y^-5)^-3

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Solution for (8x^-4y^2/-2x^2y^-5)^-3 equation: 


D( x )

x = 0

x^2*((8*x^-4*y^2)/(-2))*y^-5 = 0

x = 0

x = 0

x^2*((8*x^-4*y^2)/(-2))*y^-5 = 0

x^2*((8*x^-4*y^2)/(-2))*y^-5 = 0

-4*x^-2*y^-3 = 0 // : -4*y^-3

x^-2 = 0

x należy do O

x in (-oo:0) U (0:+oo)

(x^2*((8*x^-4*y^2)/(-2))*y^-5)^-3 = 0

-1/64*x^6*y^9 = 0 // : -1/64*y^9

x^6 = 0

x = 0

x in { 0} 

x belongs to the empty set

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